document.write( "Question 1117475: There are two numbers.When four times the larger number is added to three times the smaller number,the result is 26.If three times the larger number is decreased by twice the smaller number,the result is 11.Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #732557 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! There are two numbers.When four times the larger number is added to three times the smaller number,the result is 26.If three times the larger number is decreased by twice the smaller number,the result is 11.Find the numbers. \n" ); document.write( "------- \n" ); document.write( "Equations: \n" ); document.write( "4L+3S = 26 \n" ); document.write( "3L-2S = 11 \n" ); document.write( "---------------- \n" ); document.write( "Modify for elimination: \n" ); document.write( "12L + 9S = 3*26 \n" ); document.write( "12L - 8S = 4*11 \n" ); document.write( "--------------------------- \n" ); document.write( "Subtract and solve for \"S\":: \n" ); document.write( "Smaller = 34 \n" ); document.write( "Larger = (11+2*34)/3 = (11+68)/3 = 79/3 = 26 1/3 \n" ); document.write( "----------- \n" ); document.write( "Note:: The Larger turned out to be the Smaller. \n" ); document.write( "You might want to check your posting. \n" ); document.write( "---- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( "Ch \n" ); document.write( " |