document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117439>Question 1117439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pilot is flying from city A to city B,which is 85 miles due north after flying 20 miles ,the pilot must change course and fly 10 degree east of north to avoid a cloudbank.<BR>\n" );
document.write( "a. if the pilot   remains on this course for 20 miles how far will the plane be from city B.<BR>\n" );
document.write( "b..how many degrees will the pilot have to turn to the left TO Fly directly to city B? how many degrees from due north is this course.<BR>\n" );
document.write( "(question is from law of cosines) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732538 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\"><BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/display-illustration.mpl?tutor=solver91311&illustration_name=CourseCorrectionCrop.jpg\">.\r<BR>\n" );
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document.write( "You have side-angle-side, so use the Law of Cosines:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ t_1\ =\ \sqrt{b^2\ +\ t_2^2\ -\ 2bt_2\cos T_1}\">\r<BR>\n" );
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document.write( "where <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large t_i\"> is the side opposite angle <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large T_i\"> and <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large b\"> is the side opposite angle <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large B\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ t_1\ =\ \sqrt{20^2\ +\ 65^2\ -\ 2(20)(65)\cos 10^\circ}\">\r<BR>\n" );
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document.write( "The rest is just calculator work.  You should examine the diagram to convince yourself that the answer is going to be larger than 45 but smaller than 65 as a means of checking the reasonableness of your calculator work.\r<BR>\n" );
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document.write( "Use the Law of Sines:\r<BR>\n" );
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document.write( "  <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{Sin A}{a}\ =\ \frac{Sin B}{b}\ =\ \frac{Sin C}{c}\">\r<BR>\n" );
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document.write( "to solve the second problem in your submission.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" src=\"http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg\"><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \ \\r\"> </SPAN>\n" );
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