document.write( "Question 1117434: If each person occupies a 2ft x 2 ft area, how many people could you fit inside a triangular (equilateral)
\n" ); document.write( "concert area with a perimeter of 900 feet, and with t
\n" ); document.write( "he triangular height equal to 260 ft? \n" ); document.write( "
Algebra.Com's Answer #732520 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
If each person occupies a 2ft x 2 ft area, how many people could you fit inside a triangular (equilateral)
\n" ); document.write( "concert area with a perimeter of 900 feet, and with the triangular height equal to 260 ft?
\n" ); document.write( "-----------
\n" ); document.write( "300 ft sides --> height =~ 259.8 ft, less than 260
\n" ); document.write( "----
\n" ); document.write( "The number of 2 by 2 squares along an edge is limited to the distance parallel to the edge and 2 ft from it.
\n" ); document.write( "d = 300 - 2*2*tan(30) =~ 297.7 feet
\n" ); document.write( "--> 148 squares along an edge.
\n" ); document.write( "Each row above that is 4*tan(30) shorter.
\n" ); document.write( "The 2nd row is ~295.4 feet --> 147 squares, etc.
\n" ); document.write( "Using Excel --> 9603 people.
\n" ); document.write( "----------------------------
\n" ); document.write( "9603 times 4 = 38412 sq ft occupied of the total area of 38971 sq ft.
\n" ); document.write( "I don't think another arrangement would increase the number, but that would be difficult to prove.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );