document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100653>Question 100653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How long must a guywire be to run from the top of an 18-ft pole to a point on level ground 16 ft away from the base of the pole? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73248 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> HERE YOU HAVE A RIGHT TRIANGLE WITH SIDES OF 18 7 16 FEET. THE GUYWIRE IS THE HYPOTENUSE.<BR>\n" );
document.write( "USING THE PYTHAGOREON FORMULA WE GET:<BR>\n" );
document.write( "18^2+16^2=H^2<BR>\n" );
document.write( "324+256=H^2<BR>\n" );
document.write( "580=H^2<BR>\n" );
document.write( "H=SQRT580<BR>\n" );
document.write( "H=24.08 FEET FOR THE GUYWIRE. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );