document.write( "Question 1117366: In five years time Paula will be fifteen Janice is three years older than Paula but ten months younger than Jean how old will Jean be in three years time \n" ); document.write( "
Algebra.Com's Answer #732444 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You have to put everything in terms of
\n" ); document.write( "either months or years.
\n" ); document.write( "I will put everything in terms of years
\n" ); document.write( "--------------------------------------
\n" ); document.write( "\"+10+\" months = \"+10%2F12+\" years
\n" ); document.write( "--------------------------------------
\n" ); document.write( "Let \"+a+\" = Paula's age now
\n" ); document.write( "Let \"+b+\" = Janice's age now
\n" ); document.write( "Let \"+c+\" = Jean's age now
\n" ); document.write( "-----------------------------------
\n" ); document.write( "(1) \"+a+%2B+5+=+15+\"
\n" ); document.write( "(2) \"+b+=+a+%2B+3+\"
\n" ); document.write( "(3) \"+b+=+c+-+10%2F12+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "(1) \"+a+=+10+\"
\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) \"+b+=+10+%2B+3+\"
\n" ); document.write( "(2) \"+b+=+13+\"
\n" ); document.write( "and
\n" ); document.write( "(3) \"+13+=+c+-+10%2F12+\"
\n" ); document.write( "(3) \"+c+=+13+%2B+10%2F12+\"
\n" ); document.write( "and
\n" ); document.write( "\"+c+%2B+3+=+16+%2B+10%2F12+\"
\n" ); document.write( "In 3 years, Jean will be 16 yrs 10 mo old\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );