document.write( "Question 1117363: if the coefficients of x^k and x^(k+1) in the expansion of (2+3x)^19 are equal, find k \n" ); document.write( "
Algebra.Com's Answer #732431 by ikleyn(52810)\"\" \"About 
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document.write( "The binomial expansion is this formula\r\n" );
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document.write( "\"%28a%2Bb%29%5En\" = \"a%5En\" + \"C%5Bn%5D%5E1%2Aa%5E%28n-1%29%2Ab\" + \"C%5Bn%5D%5E2%2Aa%5E%28n-2%29%2Ab%5E2\" + \"C%5Bn%5D%5E3%2Aa%5E%28n-3%29%2Ab%5E3\" + . . . + \"C%5Bn%5D%5E%28n-1%29%2Aa%5E1%2Ab%5E%28n-1%29\" + \"b%5En\"\r\n" );
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document.write( "    (see this Wikipedia article https://en.wikipedia.org/wiki/Binomial_theorem  or my lesson\r\n" );
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document.write( "     Binomial Theorem, Binomial Formula, Binomial Coefficients and Binomial Expansion  in this site).\r\n" );
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document.write( "For our case, the term containing \"x%5Ek\" is  \"C%5B19%5D%5Ek%2A2%5E%2819-k%29%2A%283x%29%5Ek\",  while the term containing \"x%5E%28k%2B1%29\" is  \"C%5B19%5D%5E%28k%2B1%29%2A2%5E%2819-%28k%2B1%29%29%2A%283x%29%5E%28k%2B1%29\",\r\n" );
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document.write( "and they want to know at which k the coefficients at  \"x%5Ek\"  and  \"x%5E%28k%2B1%29\"  are the same:\r\n" );
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document.write( "    \"C%5B19%5D%5Ek%2A2%5E%2819-k%29%2A3%5Ek\" = \"C%5B19%5D%5E%28k%2B1%29%2A2%5E%2819-%28k%2B1%29%29%2A3%5E%28k%2B1%29\".    (1)\r\n" );
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document.write( "        (notice the difference between \"the terms\" and \"the coefficients\" !)\r\n" );
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document.write( "From (1), you have  \r\n" );
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document.write( "    \"C%5B19%5D%5Ek%2FC%5B19%5D%5E%28k%2B1%29\" = \"%282%5E19-%28k%2B1%29%2A3%5E%28k%2B1%29%29%2F%282%5E%2819-k%29%2A3%5Ek%29\",   or, simplifying the right side,   \"C%5B19%5D%5Ek%2FC%5B19%5D%5E%28k%2B1%29\" = \"3%2F2\".    (2)\r\n" );
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document.write( "Next, use  \"C%5B19%5D%5Ek\" = \"19%21%2F%28k%21%2A%2819-k%29%21%29\",  \"C%5B19%5D%5E%28k%2B1%29\" = \"19%21%2F%28%28k%2B1%29%21%2A%2819-%28k%2B1%29%29%21%29\".   \r\n" );
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document.write( "Substitute it into the left side fraction of (2),  and you will get after canceling common factors\r\n" );
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document.write( "    \"%28k%2B1%29%2F%2819-k%29\" = \"3%2F2\",\r\n" );
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document.write( "    2*(k+1) = 3*(19-k)  ====>  2k + 2 = 57 - 3k  ====>  2k + 3k = 57 - 2  ====>  5k = 55  ====>  k = \"55%2F5\" = 11.\r\n" );
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document.write( "Answer.  k = 11.\r\n" );
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