document.write( "Question 100645: Two airplanes depart from an airport traveling opposite directions. The second airplane is 200 miles per hour faster than the first. After 2 hours they are 1100 miles apart. Find the speeds of the airplanes. \n" ); document.write( "
Algebra.Com's Answer #73242 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! 2X+2(X+200)=1100 \n" ); document.write( "2X+2X+400=1100 \n" ); document.write( "4X=1100-400 \n" ); document.write( "4X=700 \n" ); document.write( "X=700/4 \n" ); document.write( "X=175 MPH. FOR THE SLOWER PLANE. \n" ); document.write( "175+200=375 MPH FOR THE FASTER PLANE. \n" ); document.write( "PROOF \n" ); document.write( "2(175+375)=1100 \n" ); document.write( "2*550=1100 \n" ); document.write( "1100=1100 \n" ); document.write( " |