document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117332>Question 1117332</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the exact value of the trigonometric expression given that tanA=3/4 and cosB=-4/5, A is in Quadrant 1 and pi < B < 3pi/2 <BR>\n" );
document.write( "The problem is sin(A+B) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732400 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  find the exact value of the trigonometric expression given that tanA=3/4 and cosB=-4/5, A is in Quadrant 1 and pi The problem is sin(A+B) <BR>\n" );
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document.write( "Sin(A+B) = sin(A)cos(B)+sin(B)cos(A)<BR>\n" );
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document.write( "Since tan(A)=(y/x) = 3/4), sin(A) = (y/r) =  3/sqrt(3^2+4^2) = 3/5<BR>\n" );
document.write( "and cos(A) =(x/4) =  4/5<BR>\n" );
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document.write( "Since cos(B)= (x/r) = -4/5, sin(B)=(y/r) = sqrt(5^2-4^2)/5 = 3/5<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Ans: sin(A+B) = (3/5)(-4/5) + (3/5)(4/5) = 0<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------ </SPAN>\n" );
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