document.write( "Question 14619: I need help with this problem. Premium coffee sells for $6.00 per pound and regular coffee sells for $4.00 per pound. How many pounds of each type of coffee should be blended to obtain 100 pounds of a blend that sells for $4.64 per pound.
\n" ); document.write( " Heres what I was doing but I am getting confused.
\n" ); document.write( "6(100) + 4x = 4.64(100-x)\r
\n" ); document.write( "\n" ); document.write( "600 + 4x =4.64 - 4.64x
\n" ); document.write( "8.64x= -136
\n" ); document.write( "I think I have messed up somewhere. \n" ); document.write( "

Algebra.Com's Answer #7324 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Ok, let x = the number of lbs of premium coffee at $6 per lb. Then (100 - x) = the number of lbs of regular coffee at $4 per lb. So you need the sum of these to make 100 lbs of blended coffee at $4.64 per lb.\r
\n" ); document.write( "\n" ); document.write( "Here's the equation:\r
\n" ); document.write( "\n" ); document.write( "x($6) + (100-x)($4) = 100($4.64) Simplify and solve for x, the number of lbs of premium coffee.\r
\n" ); document.write( "\n" ); document.write( "6x + 400 - 4x = 464
\n" ); document.write( "2x + 400 = 464 Subtract 400 from both sides.
\n" ); document.write( "2x = 64 Divide both sides by 2
\n" ); document.write( "x = 32 lbs of premium coffee. \r
\n" ); document.write( "\n" ); document.write( "100 - x = 100 - 32 = 68 lbs of regular coffee.\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "32(6) + 68(4) = 100(4.64)
\n" ); document.write( "192 + 272 = 464
\n" ); document.write( "464 = 464 Ok. \n" ); document.write( "

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