document.write( "Question 1117343: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
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\n" ); document.write( "Event : The sum is greater than 7 .
\n" ); document.write( "Event : The sum is not divisible by 3 and not divisible by 5.
\n" ); document.write( "Write your answers as exact fractions.
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Algebra.Com's Answer #732396 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "There are 36 possible outcomes:\r
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\n" ); document.write( "\n" ); document.write( "One way to make 2, two ways to make 3, ... 6 ways to make 7, 5 ways to make 8, and so on.\r
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\n" ); document.write( "\n" ); document.write( "The results greater than 7 include 8, 9, 10, 11, and 12, all together, 5 plus 4 plus 3 plus 2 plus 1 = 15. So there are 15 ways to get something larger than 7 out of 36 total outcomes.\r
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\n" ); document.write( "\n" ); document.write( "2, 4, 5, 7, 8, 10, and 11 are not divisible by 3. Of these, 5 and 10 are not divisible by 5. 1 way to make 2, 3 ways to make 4, 6 ways to make 7, 5 ways to make 8. 2 + 3 + 6 + 5 = 16 successful outcomes out of 36 total outcomes.\r
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\n" ); document.write( "\n" ); document.write( "I'm going to presume that you know how to write a fraction and reduce it to lowest terms\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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