document.write( "Question 1117289: cos2x = -cosx for 0 ≤ x < 2pi: (Round to nearest tenth.) \n" ); document.write( "
Algebra.Com's Answer #732378 by Alan3354(69443)\"\" \"About 
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cos2x = -cosx
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\n" ); document.write( "if you mean cos(2x) = -cos(x)
\n" ); document.write( "2cos^2(x) - 1 = -cos(x)\r
\n" ); document.write( "\n" ); document.write( "2cos^2(x) + cos(x) - 1 = 0
\n" ); document.write( "(2cos - 1)*(cos + 1) = 0
\n" ); document.write( "cos(x) = -1
\n" ); document.write( "x = pi
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\n" ); document.write( "2cos(x) - 1 = 0
\n" ); document.write( "cos(x) = 1/2
\n" ); document.write( "x = pi/3, 5pi/3
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