document.write( "Question 1117302: 2-logx=log5 \n" ); document.write( "
Algebra.Com's Answer #732363 by greenestamps(13215)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "There are MANY correct ways to work this problem.

\n" ); document.write( "I would definitely not use the method shown by tutor josgarithmetic, since it involves finding a numerical approximation of a logarithm.

\n" ); document.write( "The method shown by the other tutor is fine...

\n" ); document.write( "I would be inclined to rewrite the equation with every term as a logarithm and then use rules of logarithms:

\n" ); document.write( "\"2-log%2810%2Cx%29=log%2810%2C5%29\"
\n" ); document.write( "\"log%2810%2C100%29-log%2810%2Cx%29+=+log%2810%2C5%29\"
\n" ); document.write( "\"log%2810%2C100%2Fx%29+=+log%2810%2C5%29\"
\n" ); document.write( "\"100%2Fx+=+5\"
\n" ); document.write( "\"x+=+20\"
\n" ); document.write( "
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