document.write( "Question 1117305: Consider the infinite geometric series (linked below). In this image, the lower limit of the summation is \"n=1\".\r
\n" ); document.write( "\n" ); document.write( "As I am not sure how to type this in formatting on this website or how to type this in text this is a link to an image of the formula mentioned above.
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\n" ); document.write( "\n" ); document.write( "A) Write the first four terms of the series.\r
\n" ); document.write( "\n" ); document.write( "B) Does the series diverge or converge?\r
\n" ); document.write( "\n" ); document.write( "C) If the series has a sum, find the sum.
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Algebra.Com's Answer #732335 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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sum[i=1,infty] [-4*(1/3)^(n-1)]
is an understandable plain text representation of \r
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\n" ); document.write( "\n" ); document.write( "As to convergence/divergence, there are a couple of ways to look at it.\r
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\n" ); document.write( "\n" ); document.write( "You can write\r
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\n" ); document.write( "\n" ); document.write( "But is a geometric series with . Since any geometric series with converges, this series must converge.\r
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\n" ); document.write( "\n" ); document.write( "Alternatively, you can use the Series Ratio Test: A series where:\r
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\n" ); document.write( "\n" ); document.write( "where converges. Verification of the series ratio test is left as an exercise for the student.\r
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\n" ); document.write( "\n" ); document.write( "Either way, the series converges.\r
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\n" ); document.write( "\n" ); document.write( "The sum of a geometric series with a common ratio is given by:\r
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\n" ); document.write( "\n" ); document.write( "So\r
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\n" ); document.write( "\n" ); document.write( "You can verify the arithmetic for yourself.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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