document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117305>Question 1117305</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Consider the infinite geometric series (linked below). In this image, the lower limit of the summation is \"n=1\".\r<BR>\n" );
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document.write( "As I am not sure how to type this in formatting on this website or how to type this in text this is a link to an image of the formula mentioned above. <BR>\n" );
document.write( "https://postimg.cc/image/hchcwn7jr/\r<BR>\n" );
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document.write( "A) Write the first four terms of the series.\r<BR>\n" );
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document.write( "B) Does the series diverge or converge?\r<BR>\n" );
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document.write( "C) If the series has a sum, find the sum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732333 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A)  -4, -4/3, -4/9, -4/27<BR>\n" );
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document.write( "Note the first term is -4 and the common ratio(r) is 1/3<BR>\n" );
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document.write( "B) converges since |r| < 1<BR>\n" );
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document.write( "C) -4 / (1 - 1/3) = -4 * 3/2 = -6<BR>\n" );
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document.write( " </SPAN>\n" );
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