document.write( "Question 1117297: solve e^-4x=9 \n" ); document.write( "

Algebra.Com's Answer #732331 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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solve $\"e%5E%28-4x%29=9\"$
\n" ); document.write( "using natural logs
\n" ); document.write( " $\"ln%28e%5E%28-4x%29%29+=+ln%289%29\"$
\n" ); document.write( "the log equiv of exponent
\n" ); document.write( " $\"-4x%2Aln%28e%29+=+ln%289%29\"$
\n" ); document.write( "the ln of e is 1, therefore
\n" ); document.write( "-4x = 2.197
\n" ); document.write( "x = $\"2.197%2F%28-4%29\"$
\n" ); document.write( "x = -.5493
\n" ); document.write( " \n" ); document.write( "

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