document.write( "Question 1117302: 2-logx=log5 \n" ); document.write( "
Algebra.Com's Answer #732326 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
\"-log%28%28x%29%29=-2%2Blog%28%285%29%29\"
\n" ); document.write( "\"log%28%28x%29%29=2-log%28%285%29%29\"
\n" ); document.write( "\"log%28%28x%29%29=1.30103\"
\n" ); document.write( "\"10%5E1.30103=x\"
\n" ); document.write( "\"x=20\"\r
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\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "\"2-log%28%2820%29%29=0.69897=log%28%285%29%29\"
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