document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117260>Question 1117260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man is 38 years old and his daughter is 14 years old. How many years will it be before the man’s age is just twice that of his daughter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732292 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Using algebra on this problem is \"overkill\".<br><BR>\n" );
document.write( "If you need to use algebra, then the solution from the other tutor is fine.  But the problem is far more easily solved informally, using common sense.<br><BR>\n" );
document.write( "(1) The man is 38 and his daughter is 14; the difference in their ages is 24 years.<BR>\n" );
document.write( "(2) He will be twice as old as his daughter when she is 24 and he is 48.<BR>\n" );
document.write( "(3) Since he is now 38, that will be in (48-38)=10 years from now. </SPAN>\n" );
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