document.write( "Question 100604This question is from textbook
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document.write( ": At 3:10P.M. a skydiver jumps from an airplane at an altitude of 15,000 feet. At 3:10:26 at an altitude of 4200, the skydiver opens the parachute. What was the skydiver's average speed during the 26-second free-fall? \n" );
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Algebra.Com's Answer #73228 by doukungfoo(195)![]() ![]() You can put this solution on YOUR website! This problem deals with distance, speed and time. \n" ); document.write( "to find average speed you must divide distance by time. \n" ); document.write( "So first we need to find the distance traveled by the skydiver \n" ); document.write( "during his/her freefall. \n" ); document.write( "The skydiver started at an altitude of 15,000 feet and opened the parachute \n" ); document.write( "at 4200 feet. \n" ); document.write( "So the distance traveled during freefall is \n" ); document.write( "15000 - 4200 = 10800 feet \n" ); document.write( "Now just divide the distance by the time \n" ); document.write( "10800 ft / 26 seconds = average speed \n" ); document.write( "415.3846154 ft/s = average speed \n" ); document.write( "Note: since the distance unit given is feet and the time unit given \n" ); document.write( "is seconds. The answer is expressed in feet per second. (ft/s) \n" ); document.write( "Also you can round the answer or not depending if specified by your \n" ); document.write( "instructor or text book. \n" ); document.write( "For example the answer rounded to the nearest whole foot would be: \n" ); document.write( "415 ft/s \n" ); document.write( " \n" ); document.write( " |