document.write( "Question 100588: (2y-3)^2=5 solve \n" ); document.write( "
Algebra.Com's Answer #73223 by tutorcecilia(2152)\"\" \"About 
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\"%28sqrt%28%282y-3%29%5E2%29%29\" = \"%28sqrt%285%29%29\"
\n" ); document.write( "\"%282y-3%29%29\" = \"%28sqrt%285%29%29\"
\n" ); document.write( "\"%282y-3%2B3%29%29\" = 3+-\"%28sqrt%285%29%29\"
\n" ); document.write( "\"%282y%2F2%29%29\" = (3/2) +- \"%28%28sqrt%285%29%29%29%2F2\"
\n" ); document.write( "y= (3+-(sqrt5)/2 [the entire quantity is over 2
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