document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117187>Question 1117187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The age of Mrs. Cruz is 9 years more than three times her son's age. Find the age of each if fifteen years from now, she will be 6 years more than twice her son's age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732183 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732183\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let Mrs. Cruz's son's age be x and Mrs. Cruz's age by y<BR>\n" );
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document.write( "1) y = 3x +9<BR>\n" );
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document.write( "substitute for y in equation 2 using equation 1<BR>\n" );
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document.write( "2) y +15 = 2(x+15) +6<BR>\n" );
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document.write( "3x+9 +15 = 2x +30 +6<BR>\n" );
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document.write( "3x +24 = 2x +36<BR>\n" );
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document.write( "x = 12 and y = 45<BR>\n" );
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document.write( "Mrs. Cruz's son is 12 and Mrs. Cruz is 45<BR>\n" );
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