document.write( "Question 1117165: A rectangular garden, measuring 20m by 15 m, has a uniform strip removed from the edge of one length and the edge of one width to make a concrete walkway. If the area of the remaining garden is 204m squared , what is the width of the walkway \n" ); document.write( "

Algebra.Com's Answer #732157 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Area=Length times Width or A=LW
\n" ); document.write( "Let x=width of walkway
\n" ); document.write( "Original area is 20 times 15=300 sq meters
\n" ); document.write( "Area after walkway is installed is (15-x) times (20-x)=204 sq meters
\n" ); document.write( "(15-x)(20-x)=204\r
\n" ); document.write( "\n" ); document.write( "300-35x+x^2=204
\n" ); document.write( "x^2-35x+96=0 Quadratic in standard form: Solve using quadratic formula
\n" ); document.write( "x=(35+-sqrt((-35)^2-4*1*96))/2
\n" ); document.write( "x=(35+-sqrt(1225-384))/2
\n" ); document.write( "x=(35+-sqrt(841))/2
\n" ); document.write( "x=(35+-29)/2
\n" ); document.write( "x=(64)/2= 32 meters unrealistic
\n" ); document.write( "and
\n" ); document.write( "x=6/2= 3 meters answer\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "(15-3)(20-3)=204
\n" ); document.write( "(12)(17)=204
\n" ); document.write( "204=204\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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