document.write( "Question 1117121: if x^2 -16√(x) =12 then x-2√(x) = ?? \n" ); document.write( "
Algebra.Com's Answer #732153 by ikleyn(52786)\"\" \"About 
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document.write( "Let me introduce new variable  u = \"sqrt%28x%29\".\r\n" );
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document.write( "Then I can reformulate the problem in this EQUIVALENT way:\r\n" );
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document.write( "    If  \"u%5E4+-+16u\" = \"12\",  then find  \"u%5E2+-+2u\".\r\n" );
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document.write( "If  \"u%5E4+-+16u\" = \"12\",   then\r\n" );
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document.write( "    \"u%5E4+-+16u+-+12\" = 0.    (1)\r\n" );
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document.write( "The left side can be factored:\r\n" );
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document.write( "    \"u%5E4+-+16u+-+12\" = \"%28u%5E2-2u-2%29\".\"%28u%5E2%2B2u%2B6%29\"\r\n" );
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document.write( "into the product of two quadratic polynomials.  (You may check the validity of this decomposition on your own).\r\n" );
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document.write( "Thus the equation (1) is equivalent to\r\n" );
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document.write( "    \"%28u%5E2-2u-2%29\".\"%28u%5E2%2B2u%2B6%29\" = 0.     (2)\r\n" );
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document.write( "If \"u\" is the real root of the equation (1),  then \"u\" is the real root of the equation (2).\r\n" );
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document.write( "But the second polynomial (second multiplier)  \"%28u%5E2%2B2u%2B6%29\"  is positively defined quadratic function  \"%28u%2B1%29%5E2%2B5\",  which has NO real roots.\r\n" );
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document.write( "Therefore, \"u\" is the root of the first trinomial  of (2),  i.e.\r\n" );
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document.write( "    \"u%5E2-2u-2\" = 0,\r\n" );
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document.write( "Then  \"u%5B1%2C2%5D\" = \"%282+%2B-+sqrt+%28%28-2%29%5E2%2B4%2A2%29%29%2F2\" = \"%282+%2B-+sqrt%2812%29%29%2F2\" = \"1+%2B-+sqrt%283%29\".\r\n" );
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document.write( "Now, if  \"u\" = \"1+%2Bsqrt%283%29\",  then  \"u%5E2-2u\" = \"%281%2Bsqrt%283%29%29%5E2-2%2A%281%2Bsqrt%283%29%29\" = \"4+%2B+2%2Asqrt%283%29+-+2+-+2%2Asqrt%283%29\" = 2.\r\n" );
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document.write( "     If  \"u\" = \"1+-sqrt%283%29\",  then  \"u%5E2-2u\" = \"%281-sqrt%283%29%29%5E2-2%2A%281-sqrt%283%29%29\" = \"4+-+2%2Asqrt%283%29+-+2+%2B+2%2Asqrt%283%29\" = 2.\r\n" );
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document.write( "    \r\n" );
document.write( "Thus in any case  \"u%5E2-2u\" = 2.\r\n" );
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document.write( "It is the answer to the problem question.\r\n" );
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document.write( "Answer.  If x is a real number such as  \"x%5E2+-+sqrt%28x%29\" = \"12\",  then  \"x-2sqrt%28x%29\" = 2.\r\n" );
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