document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117125>Question 1117125</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the following:<BR>\n" );
document.write( "a. the 11th term in the geometric sequence given that a1 = -3 and a2 = 9<BR>\n" );
document.write( "b. the sum of the first 10 terms of the geometric sequence 5, 15, 45, ....\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732135 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732135\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find the following:<BR>\n" );
document.write( "a. the 11th term in the geometric sequence given that a1 = -3 and a2 = 9<BR>\n" );
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document.write( "r = 9/(-3) = -3<BR>\n" );
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document.write( "A(11) = a(1)*r^(11-1) = -3*(-3)^10 = (-3)^11 = -177147<BR>\n" );
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document.write( "b. the sum of the first 10 terms of the geometric sequence 5, 15, 45, ....<BR>\n" );
document.write( "a(1) = 5<BR>\n" );
document.write( "r = 15/5 = 3<BR>\n" );
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document.write( "a(10) = 5*3^9 = 98415<BR>\n" );
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document.write( "S(n) = a(1)[(r^n - 1)/(r-1) <BR>\n" );
document.write( "S(10) = 5[98414/2] = 5*49207 = 246035<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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