document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117126>Question 1117126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The weight of oranges growing in an orchard is normally distributed with a mean weight of 5 oz. and a standard deviation of 1.5 oz. Using the empirical rule, determine what interval would represent weights of the middle 68% of all oranges from this orchard. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732131 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The weight of oranges growing in an orchard is normally distributed with a mean weight of 5 oz. and a standard deviation of 1.5 oz. Using the empirical rule, determine what interval would represent weights of the middle 68% of all oranges from this orchard. <BR>\n" );
document.write( "----<BR>\n" );
document.write( "Note:: If 68% is in the middle there must be two tails of 16% each.<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Find the z-value limiting those two tails::<BR>\n" );
document.write( "invNorm(0.16) = -1 and -invNorm(0.16) = +1<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Lower weight limit = 5-1*1.5 = 3.5 oz<BR>\n" );
document.write( "Upper weight limit = 5+1*1.5 = 6.5 oz<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Cheers<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
document.write( "\n" );
document.write( "--- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );