document.write( "Question 1117122: Given that f(x) = x^2 + 2, with a domain of x = [0, ∞), find the following:\r
\n" ); document.write( "\n" ); document.write( "(f^-1)(x) = [also give domain of the inverse function]\r
\n" ); document.write( "\n" ); document.write( "f(3) =\r
\n" ); document.write( "\n" ); document.write( "(f^-1)(-7) = \n" ); document.write( "
Algebra.Com's Answer #732108 by rothauserc(4718)\"\" \"About 
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y = x^2 +2
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\n" ); document.write( "interchange the y's and x's and solve for y
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\n" ); document.write( "x = y^2 +2
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\n" ); document.write( "y = square root(x -2)
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\n" ); document.write( "f^(-1) (x) = square root(x -2)
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\n" ); document.write( "domain of f^(-1) (x) is [2, infinity)
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\n" ); document.write( "f(3) = 3^2 +2 = 11
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\n" ); document.write( "f^(-1) (-7) is not defined since the domain of f^(-1) (x) does not include negative numbers
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\n" ); document.write( "Note if negative numbers are allowed then f^(-1) (-7) = i * square root(9) which gives us two answers 3i and -3i, i is the square root(-1)
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