document.write( "Question 1117081: If two resistors with resistance R1 and R2 are connected in parallel, the total resistance R in ohms is given by 1/R = 1/R1 + 1/R2. If R1 and R2 are increasing at 0.4 ohms/s and 0.25 ohms/s, respectively, how fast is R changing when R1 = 600 ohms and R2 = 400 ohms? \n" ); document.write( "
Algebra.Com's Answer #732078 by Alan3354(69443) You can put this solution on YOUR website! If two resistors with resistance R1 and R2 are connected in parallel, the total resistance R in ohms is given by 1/R = 1/R1 + 1/R2. If R1 and R2 are increasing at 0.4 ohms/s and 0.25 ohms/s, respectively, how fast is R changing when R1 = 600 ohms and R2 = 400 ohms? \n" ); document.write( "------------------ \n" ); document.write( "I'll use x or R1 and y for R2 for clarity and to save typing. \n" ); document.write( "1/R = 1/x + 1/y \n" ); document.write( "R^-1 = x^-1 + y^-1 \n" ); document.write( "R = 600*400/1000 = 240 ohms \n" ); document.write( "------ \n" ); document.write( "Differentiate implicitly \n" ); document.write( "-R^-2*dR/dt = -x^-2*dx/dt - y^-2*dy/dt \n" ); document.write( "(dR/dt)/R^2 = (dx/dt)/x^2 + (dy/dt)/y^2 \n" ); document.write( "(dR/dt)/240^2 = 0.4/600^2 + 0.25/400^2 \n" ); document.write( "dR/dt = 0.4*240^2/600^2 + 0.25*240^2/400^2 \n" ); document.write( "dR/dt = 0.4*2^2/5^2 + 0.25*6^2/10^2 \n" ); document.write( "dR/dt = 0.4*4/25 + 0.25*36/100 \n" ); document.write( "dR/dt = 6.4/100 + 9/100 = 15.4/100 \n" ); document.write( "dR/dt = 0.154 ohms/sec \n" ); document.write( "============================== \n" ); document.write( "I've done resistor problems since the 1950's, but have never seen one like this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |