document.write( "Question 1117096: Given that tan A=1/5. Find the values of tan 2A, tan 4A and tan (45°-4A).
\n" ); document.write( "I have calculated the value of tan 2A by using tan 2A = 2tan A/1-tan^2A and the answer I have got is 5/12. Now I don't know how to solve further. Please give me a idea for it.
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Algebra.Com's Answer #732070 by ikleyn(52835)\"\" \"About 
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document.write( "1.  tan(2A) = \"%282%2Atan%28A%29%29%2F%281-tan%5E2%28A%29%29\" = \"%282%2A%281%2F5%29%29%2F%281-%281%2F5%29%5E2%29\" = \"%28%282%2F5%29%29%2F%281-1%2F25%29\" = \"%28%282%2F5%29%29%2F%2824%2F25%29%29\" = \"%282%2A25%29%2F%285%2A24%29\" = \"5%2F12\".\r\n" );
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document.write( "    So, your calculations for tan(2A) are correct.\r\n" );
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document.write( "2.  To calculate  tan(4A),  notice that  4A = 2*(2A);  thus  tan(4A) = tan(2*(2A)).\r\n" );
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document.write( "    So, you can repeat THE SAME PROCEDURE  to get  tan(4A)  starting from  tan(2A), which you just know.\r\n" );
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document.write( "3.  tan(45°-4A) = \"%28tan%2845%5Eo%29-tan%284A%29%29%2F%281%2Btan%2845%5Eo%29%2Atan%284A%29%29\" = \"%281-tan%284A%29%29%2F%281%2Btan%284A%29%29\".\r\n" );
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document.write( "    So, when you will find  tan(4A)  (as I described in n.2), you will be in position to find  tan(45°-4A).\r\n" );
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