document.write( "Question 1117087: New York City and Houston are 1600 miles apart. Because the jet stream blows towards the East, flights from Houston to New York take 1/2 an hour less than flights from New York to Houston. If a commercial jet flies 520 MPH how fast does the jest stream blow? \n" ); document.write( "
Algebra.Com's Answer #732062 by ikleyn(52810)\"\" \"About 
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document.write( "Let v be the rate of the jet stream, in miles per hour.\r\n" );
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document.write( "Then the effective speed of the plane flying with the wind is (520+v) mph, and the time of the flight with tailwind is \"1600%2F%28520%2Bv%29\" hours.\r\n" );
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document.write( "    The effective speed of the plane flying against the wind is (520-v) mph, and the time of the flight with headwind is \"1600%2F%28520-v%29\" hours.\r\n" );
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document.write( "The time difference is  \"1%2F2\"  of an hour,  which gives you an equation\r\n" );
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document.write( "\"1600%2F%28520-v%29\" - \"1600%2F%28520%2Bv%29\" = \"1%2F2\".\r\n" );
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document.write( "To solve it, multiply both sides by  2*(520-v)*(520+v).  You will get\r\n" );
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document.write( "2*1600*(520+v) - 2*1600*(520-v) = (520-v)*(520+v)\r\n" );
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document.write( "2*1600*v + 2*1600*v = 520^2 - v^2\r\n" );
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document.write( "v^2 + 6400v = 520^2\r\n" );
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document.write( "v^2 + 2*3200 + 3200^2 = 520^2 + 3200^2\r\n" );
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document.write( "\"%28v+%2B+3200%29%5E2\" = 10510400\r\n" );
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document.write( "v + 3200 = +/- \"sqrt%2810510400%29\"\r\n" );
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document.write( "v = - 3200 + 3241.975 = 41.975.\r\n" );
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document.write( "Check.  \"1600%2F%28520-41.975%29\" - \"1600%2F%28520%2B41.975%29\" = 0.5.   ! Correct !\r\n" );
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document.write( "Answer.  The rate of the jet stream was  41.975 mph.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "It is a typical \"tailwind and headwind\" word problem.\r
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\n" ); document.write( "\n" ); document.write( "See the lessons \r
\n" ); document.write( "\n" ); document.write( "    - Wind and Current problems \r
\n" ); document.write( "\n" ); document.write( "    - Wind and Current problems solvable by quadratic equations \r
\n" ); document.write( "\n" ); document.write( "    - Selected problems from the archive on a plane flying with and against the wind \r
\n" ); document.write( "\n" ); document.write( "in this site, where you will find other similar solved problems with detailed explanations.\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this textbook under the section \"Word problems\",  the topic \"Travel and Distance problems\".\r
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\n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I
\n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r
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\n" ); document.write( "\n" ); document.write( "I agree with the @Alan's note that the geographical settings in this problem are FAR from to be perfect.\r
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