document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117064>Question 1117064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A  land scaper sights the top of a tree at a 68 degree angle.she then moves an additional 70 feet directly away from the tree and sights the top at a 43 degree angle.how tall is the tree to the nearest tenth of a foot. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732030 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A landscaper sights the top of a tree at a 68 degree angle.she then moves an additional 70 feet directly away from the tree and sights the top at a 43 degree angle.how tall is the tree to the nearest tenth of a foot.<BR>\n" );
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document.write( "height = base*tan(68)<BR>\n" );
document.write( "height = (base+70)tan(43)<BR>\n" );
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document.write( "base*tan(68) - base*tan(43) = 70*tan(43)<BR>\n" );
document.write( "base = 70*tan(43)/[tan(68)-tan(43)] = 42.32<BR>\n" );
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document.write( "Ans:: height = 42.32*tan(68) = 104.74 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H  </SPAN>\n" );
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