document.write( "Question 100545: separate the number 78 into three parts so that the second part is twice the first part and the third part is 6 more than the first part \n" ); document.write( "

Algebra.Com's Answer #73197 by Earlsdon(6294) $\"\"$ $\"About$

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Let x be the first part, then 2x is the second part and x+6 is the third part.
\n" ); document.write( "x + 2x + x+6 = 78
\n" ); document.write( "4x+6 = 78
\n" ); document.write( "4x = 72
\n" ); document.write( "x = 18
\n" ); document.write( "2x = 36
\n" ); document.write( "x+6 = 24
\n" ); document.write( "Check:
\n" ); document.write( "18+36+24 = 78 \n" ); document.write( "

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