document.write( "Question 1116990: If tan (A+B)= x and tan B =1/2 prove that tan A=2x-1/x+2 and obtain an expression in terms of x. If tan (A-B)=1/3 and A is acute ,find without using tables.
\n" ); document.write( "My solution:
\n" ); document.write( "On using tan(A+B) formula
\n" ); document.write( "X=(tan A +1/2)/1-tan.1/2
\n" ); document.write( "X=[(2tan A+1)/2]/1-tanA/2
\n" ); document.write( "X=[(2tan A+1)/2)]/(2-tan A)/2
\n" ); document.write( "X=(2tan A+1/2)*2/2-tan A
\n" ); document.write( "X=2tan A+1/2-tan A
\n" ); document.write( "2x-x tan A=2tan A +1
\n" ); document.write( "2x-1=2tan A+tan A
\n" ); document.write( "2x-1/2-x=tan A
\n" ); document.write( "And I have got
\n" ); document.write( "tan(A-B)= 3x-4/4x+3
\n" ); document.write( "Third part I am not getting please explain me
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Algebra.Com's Answer #731960 by ikleyn(52873)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "If tan (A+B)= x and tan B =1/2 prove that tan A=2x-1/x+2
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document.write( "tan(A) = tan((A + B)-B) = apply the formula for the tan of difference = \r\n" );
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document.write( "       = \"%28tan%28A%2BB%29+-+tan%28B%29%29%2F%281+%2B+tan%28A%2BB%29%2Atan%28B%29%29\" = \"%28x-1%2F2%29%2F%281%2Bx%2A%281%2F2%29%29\" = \"%28%282x-1%29%2F2%29%2F%28%282%2Bx%29%2F2%29\" = \"%282x-1%29%2F%282%2Bx%29\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "The last question,  \"find without using tables\",  is  UNCOMPLETED,  since it does not determine WHAT to find.\r
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