document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100545>Question 100545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> separate the number 78 into three parts so that the second part is twice the first part and the third part is 6 more than the first part </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73196 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> separate the number 78 into three parts so that the second part is twice the first part and the third part is 6 more than the first part<BR>\n" );
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document.write( "Let the 1st part be \"x\"<BR>\n" );
document.write( "Then 2nd part is \"2x\"<BR>\n" );
document.write( "And 3rd part is \"x+6\"<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "x + 2x + x+6 = 78<BR>\n" );
document.write( "4x+6=78<BR>\n" );
document.write( "x = 72/4= 18 (1st part)<BR>\n" );
document.write( "2x = 36 (2nd part)<BR>\n" );
document.write( "x+6 = 24 (3rd part)<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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