document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1116992>Question 1116992</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 28 cm. Find the range of possible values of the width of the rectangle if the<BR>\n" );
document.write( "diagonal is less than 10 cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #731928 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=731928\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 28 cm. Find the range of possible values of the width of the rectangle if the diagonal is less than 10 cm.<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "L + W = 14<BR>\n" );
document.write( "L^2 + w^2 < 100<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "It's obvious that 6 by 8 --> diagonal = 10, 2 times the 3, 4, 5 right triangle.<BR>\n" );
document.write( "--> 6 < W < 8 </SPAN>\n" );
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