document.write( "Question 1116963: if angle is in Quadrant II, express the remaining trigonometric functions in terms of sin(angle). \n" ); document.write( "
Algebra.Com's Answer #731917 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if your angle is in quadrant 2, then:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sine is positive. \n" ); document.write( "cosine is negative. \n" ); document.write( "tangent is negative because it is sine / cosine = positive / negative = negative. \n" ); document.write( "cosecant is reciprocal of sine, therefore also positive. \n" ); document.write( "secant is reciprocal of cosine, therefore also negative. \n" ); document.write( "cotangent is reciprocal of tangent, therefore also negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a reference on the sign of the trigonometric functions in each quadrant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://www.sparknotes.com/math/trigonometry/trigonometricfunctions/section3/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the rules are summarized another way below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sine is positive in first and second quadrant. \n" ); document.write( "cosine is positive in first and fourth quadrant. \n" ); document.write( "tangent is positive in first and third quadrant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sine is negative in third and fourth quadrant. \n" ); document.write( "cosine is negative in second and third quadrant. \n" ); document.write( "tangent is negative in second and fourth quadrant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it all has to do with the unit circle, which is used to display the angles in each quadrant and to find their associated trigonometric functions.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the radius of this unit circle is equal to 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the horizontal sides of the angles formed are on the x-axis.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the vertical sides of the angles formed are parallel to the y-axis.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "becauwe the radius of the circle is also the hypotenuse of the triangles formed, then the length of the hypotenuse of the triangles formed is always equal to 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this results in the sine funtion always being equal to y and the cosine function always being equal to x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for example:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sine of angle = y/h. \n" ); document.write( "since h = 1, then sine of angle = y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cosine of angle = x/h. \n" ); document.write( "since h = 1, then cosine of angle = x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the sine function is positive when y is positive which is when y is above the x-axis.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the cosine function is positive when x is positive which is when x is to the right of the y-axis.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the tangent function is positive when x and y are both positive or when x and y are both negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's my picture that should help you see what i mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "h = hypotenuse \n" ); document.write( "x = side of triangle that is adjacent to the angle. \n" ); document.write( "y = side of triangle that is opposite to the angle.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |