document.write( "Question 1116952: You can afford a monthly mortgage payment of $1,650 and can get a 15-year 5.625% loan. What is the maximum loan you can get so your payment does not exceed $1,650? \n" ); document.write( "
Algebra.Com's Answer #731903 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The formula to compute the monthly payment is
\n" ); document.write( "\"P+=+L%2A%28c%281%2Bc%29%5En%29%2F%28%281%2Bc%29%5En-1%29\"
\n" ); document.write( "where,
\n" ); document.write( "L = loan amount
\n" ); document.write( "P = monthly payment
\n" ); document.write( "c = interest rate per period
\n" ); document.write( "n = number of periods\r
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\n" ); document.write( "\n" ); document.write( "In this case,
\n" ); document.write( "L = unknown
\n" ); document.write( "P = 1650
\n" ); document.write( "c = r/12 = 0.05625/12 = 0.0046875
\n" ); document.write( "n = 12*y = 12*15 = 180 months\r
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\n" ); document.write( "\n" ); document.write( "Plug in the given info. Then solve for L
\n" ); document.write( "\"P+=+L%2A%28c%281%2Bc%29%5En%29%2F%28%281%2Bc%29%5En-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1650+=+L%2A%280.0046875%281%2B0.0046875%29%5E180%29%2F%28%281%2B0.0046875%29%5E180-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1650+=+L%2A%280.0046875%281.0046875%29%5E180%29%2F%28%281.0046875%29%5E180-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1650+=+L%2A%280.0046875%2A2.32049057740442%29%2F%282.32049057740442-1%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1650+=+L%2A%280.01087729958159%29%2F%281.32049057740442%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1650+=+L%2A0.00823731707572\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281650%29%2F%280.00823731707572%29+=+%28L%2A0.00823731707572%29%2F%280.00823731707572%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"200307.938231912+=+L\"\r
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\n" ); document.write( "\n" ); document.write( "\"L+=+200307.938231912\"
\n" ); document.write( "Round to the nearest dollar to get L = 200308. This is the max L can be so that P does not exceed 1650 If L = 200308, then P = 1650.\r
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\n" ); document.write( "\n" ); document.write( "Final Answer: 200308 dollars
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