document.write( "Question 1116969: Jill is 2 times as old as Amanda. The sum of their ages 7 years ago was 13. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #731897 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "J = Jill's current age \n" ); document.write( "A = Amanda's current age\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "J = 2*A because \"Jill is 2 times as old as Amanda\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Seven years ago, Jill was J-7 years old and Amanda was A-7 years old. The sum of their ages back then was 13, so, \n" ); document.write( "(J-7)+(A-7) = 13 \n" ); document.write( "J+A-14 = 13 \n" ); document.write( "J+A-14+14 = 13+14 \n" ); document.write( "J+A = 27\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in J = 2A and solve for A \n" ); document.write( "J+A = 27 \n" ); document.write( "2A+A = 27 \n" ); document.write( "3A = 27 \n" ); document.write( "A = 27/3 \n" ); document.write( "A = 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use this to find J \n" ); document.write( "J = 2*A \n" ); document.write( "J = 2*9 \n" ); document.write( "J = 18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jill is 18 years old currently. Amanda is 9 years old currently.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As a check, if we go back 7 years then Jill is now 11 years old while Amanda is 2 years old. Their past ages sum to 11+2 = 13. \n" ); document.write( " \n" ); document.write( " |