document.write( "Question 1116916: 3.1 It is estimated that 30% of all drivers have some kind of medical aid in South Africa. What is the
\n" ); document.write( "probability that in a sample of 10 drivers:
\n" ); document.write( "3.1.1 Exactly 4 will have a medical aid.
\n" ); document.write( "3.1.2 At least 2 will have a medical aid.
\n" ); document.write( "3.1.3 More than 9 will have a medical aid. \r
\n" ); document.write( "\n" ); document.write( "3.2 Sun Couriers, a parcel delivery company, has found that the delivery time of parcels to clients in
\n" ); document.write( "the Durban metropolitan area after airport collection is normally distributed with a mean
\n" ); document.write( "delivery time equal 45minutes (ľ = 45) and a standard deviation of 8 minutes (α=8).
\n" ); document.write( "For a newly arrived consignment at Durban airport, what is the probability that a randomly
\n" ); document.write( "selected parcel will take: Between 45 and 51 minutes to deliver to the client \n" ); document.write( "

Algebra.Com's Answer #731864 by Boreal(15235) $\"\"$ $\"About$

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1: 10C4(.3)^4*.7^6=0.2001
\n" ); document.write( "2: 10C2(.3^2)*.7^8=0.2335
\n" ); document.write( "3: That is all 10, which is .3^10=0.0000059
\n" ); document.write( "z=(x-mean)/sd
\n" ); document.write( "z=(51-45)/8=0.75
\n" ); document.write( "probability z is between 0 and 0.75, since 45 is z=0
\n" ); document.write( "This is 0.2734 \n" ); document.write( "

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