document.write( "Question 1116940: Suppose that you are taking a course that has 4 tests. The first three tests are each worth 20% of your final grade, and the fourth test is worth 40% of the final grade. To get a B in the course, you must have an average of at least 80 percent on the 4 tests. Your scores on the first 3 tests were
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document.write( "65.5%,
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document.write( "71%, and
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document.write( "94%. What is the minimum score you need on the fourth test to get a B for the course?. Don't round your answer. \n" );
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Algebra.Com's Answer #731858 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Let each test count as 1 and the fourth test count as 2 \n" ); document.write( "average=total/n \n" ); document.write( "80=400/5. The tests count as 1, so the total is 65.5+71+94=230.5 \n" ); document.write( "That leaves 169.5 left to make 400, 400-230.5 \n" ); document.write( "That is the score the final will contribute, and it counts twice, so divide by 2 to get 84.75. \n" ); document.write( " |