document.write( "Question 1116894: A sinusoidal function has an amplitude of 3 units, a maximum at (0,4), and a period of 180 degrees. Represent the function using both sine and cosine functions. \n" ); document.write( "
Algebra.Com's Answer #731827 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "We want equations in the form

\n" ); document.write( "\"a%2Asin%28b%28x-c%29%29%2Bd\"

\n" ); document.write( "and

\n" ); document.write( "\"a%2Acos%28b%28x-c%29%29%2Bd\"

\n" ); document.write( "The function has an amplitude of 3; so a in both equations is 3.

\n" ); document.write( "The function has a maximum value of 4. An amplitude of 3 and a maximum value of 4 means the minimum value is -2, and the centerline (d in each equation) 1.

\n" ); document.write( "The period is 180 degrees, which is half the period of the basic sine or cosine function. That means b is 2.

\n" ); document.write( "Those are the relatively easy parts of the problem. We have as the two equations

\n" ); document.write( "\"3%2Asin%282%28x-c%29%29%2B1\" and \"3%2Acos%282%28x-c%29%29%2B1\"

\n" ); document.write( "By far the hardest part (for most students) is finding the values for c in each equation. That value determines the phase (horizontal) shift for the function.

\n" ); document.write( "The given function has a maximum at x=0. The basic cosine function has a maximum value at x=0, so there is no phase shift. So the cosine equation for your example is

\n" ); document.write( "\"3%2Acos%282x%29%2B1\"

\n" ); document.write( "For the sine function, the maximum occurs 1/4 of the way through the period; since the period of the function is 180 degrees (pi radians), the phase shift is 45 degrees (pi/4 radians) to the left. So the phase shift c is -pi/4 (making \"x-c\" equal to \"x+pi/4\"), and the sine function is

\n" ); document.write( "\"3%2Asin%282%28x%2Bpi%2F4%29%29%2B1\"

\n" ); document.write( "or

\n" ); document.write( "\"3%2Asin%282x%2Bpi%2F2%29%2B1\"

\n" ); document.write( "The first form is more meaningful to me, because I can see the phase shift of pi/4 clearly.
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