document.write( "Question 1116863: A farmer bought some sheep for $2100. Two sheep died, and he sold the rest for $30 more a head than he paid for them. If he made a profit of $60, how many sheep did he buy? \n" ); document.write( "
Algebra.Com's Answer #731826 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The solution by tutor ikleyn is fine. \n" ); document.write( "Here is a different path which leads to the same equation to solve and of course the same answer. \n" ); document.write( "Always be open to trying different methods for solving problems to find what methods \"work\" best for you. \n" ); document.write( "If the original number of sheep is n, then the cost for each one was 2100/n. \n" ); document.write( "Two of the sheep died, so the number he sold was (n-2). \n" ); document.write( "He sold them for $30 more a head than he paid for them; so the selling price was (2100/n+30). \n" ); document.write( "Selling (n-2) sheep for that price made him a profit of $60, so he sold them for a total of $2160. \n" ); document.write( "So \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The number of sheep he bought was n=14. \n" ); document.write( " |