document.write( "Question 1116863: A farmer bought some sheep for $2100. Two sheep died, and he sold the rest for $30 more a head than he paid for them. If he made a profit of $60, how many sheep did he buy? \n" ); document.write( "
Algebra.Com's Answer #731826 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The solution by tutor ikleyn is fine.

\n" ); document.write( "Here is a different path which leads to the same equation to solve and of course the same answer.

\n" ); document.write( "Always be open to trying different methods for solving problems to find what methods \"work\" best for you.

\n" ); document.write( "If the original number of sheep is n, then the cost for each one was 2100/n.

\n" ); document.write( "Two of the sheep died, so the number he sold was (n-2).

\n" ); document.write( "He sold them for $30 more a head than he paid for them; so the selling price was (2100/n+30).

\n" ); document.write( "Selling (n-2) sheep for that price made him a profit of $60, so he sold them for a total of $2160.

\n" ); document.write( "So

\n" ); document.write( "\"%282100%2Fn%2B30%29%28n-2%29+=+2160\"
\n" ); document.write( "\"2100-4200%2Fn%2B30n-60+=+2160\"
\n" ); document.write( "\"30n-4200%2Fn+=+120\"
\n" ); document.write( "\"n-140%2Fn=4\"
\n" ); document.write( "\"n-4-140%2Fn=0\"
\n" ); document.write( "\"n%5E2-4n-140=0\"
\n" ); document.write( "\"%28n-14%29%28n%2B10%29+=+0\"
\n" ); document.write( "\"n+=+14\"

\n" ); document.write( "The number of sheep he bought was n=14.
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