document.write( "Question 1116864: Carlos takes 3 hours longer than Ty to walk 30 miles; but if Carlos doubles his pace, he takes 2 hours less than Ty. Find (a) the rate at which Carlos walks and (b) the rate at which Ty walks. \n" ); document.write( "
Algebra.Com's Answer #731810 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+t+\" = Ty's time in hrs to walk \"+30+\" mi.
\n" ); document.write( "when he walks at rate \"+r+\" in mi/hr
\n" ); document.write( "\"+t+%2B+3+\" = Carlos's time to do this
\n" ); document.write( "--------------------------------------------
\n" ); document.write( "Carlos's rate is \"+30%2F%28+t+%2B+3+%29+\"
\n" ); document.write( "Double this rate is \"+60%2F%28+t%2B3+%29+\"
\n" ); document.write( "Carlos's time at this rate is \"+t+-+2+\"
\n" ); document.write( "--------------------------------------------
\n" ); document.write( "Ty's equation:
\n" ); document.write( "\"+30+=+r%2At+\"
\n" ); document.write( "\"+r+=+30%2Ft+\"
\n" ); document.write( "Carlos's equation:
\n" ); document.write( "\"+30+=+%28+60%2F%28+t%2B3+%29+%29%2A%28+t+-+2+%29+\"
\n" ); document.write( "\"+30%2A%28+t%2B3+%29+=+60%2A%28+t+-+2+%29+\"
\n" ); document.write( "\"+t+%2B+3+=+2%2A%28+t+-+2+%29+\"
\n" ); document.write( "\"+t+%2B+3+=+2t+-+4+\"
\n" ); document.write( "\"+t+=+7+\"
\n" ); document.write( "--------------------
\n" ); document.write( "Ty's rate is:
\n" ); document.write( "\"+r+=+30%2Ft+\"
\n" ); document.write( "\"+r+=+30%2F7+\" mi/hr
\n" ); document.write( "----------------------
\n" ); document.write( "Carlos's rate is:
\n" ); document.write( "\"+30%2F+%28+t+%2B+3+%29+=+30%2F%28+7+%2B+3+%29+\"
\n" ); document.write( "\"+30%2F10++=+3+\" mi/hr
\n" ); document.write( "----------------------------------
\n" ); document.write( "check:
\n" ); document.write( "Double Carlos's pace is \"+6+\" mi/hr
\n" ); document.write( "Two hrs less tiome than Ty is \"+7+-+2+=+5+\" hrs
\n" ); document.write( "\"+30+=+6%2A5+\"
\n" ); document.write( "OK\r
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