document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1116885>Question 1116885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this Finite Math problem!<BR>\n" );
document.write( " a consumer set out to compare prices on premiums of comparable insurance policies offered by three companies: Country Farm, Metma, and Wisely. She found that Country Farm was $35 higher than Metma but $25 lower than Wisely. Wisely was $155 less than the sum of the premiums of the other two. Find the premium charged by each company </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #731789 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=731789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let c = premium charged by country farm.<BR>\n" );
document.write( "let m = premium charged by metma.<BR>\n" );
document.write( "let w = premium charged by wisely.\r<BR>\n" );
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document.write( "country farm charges 35 more than metma, therefore c = m + 35\r<BR>\n" );
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document.write( "country farm charges 25 less than wisely, therefore c = w - 25\r<BR>\n" );
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document.write( "wisely charges 155 less than the sum of the premiums of country farm and metma, therefore w = c + m - 155\r<BR>\n" );
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document.write( "you have 3 equations that need to be solved simultaneously.,\r<BR>\n" );
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document.write( "they are:\r<BR>\n" );
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document.write( "c = m + 35 (first original equation)<BR>\n" );
document.write( "c = w - 25 (second original equation)<BR>\n" );
document.write( "w = c + m - 155 (third original equation)\r<BR>\n" );
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document.write( "rearrange the terms in each equation so that the variables are on the left and the constants are on the right.\r<BR>\n" );
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document.write( "the equations become:\r<BR>\n" );
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document.write( "c - m = 35<BR>\n" );
document.write( "c - w = -25<BR>\n" );
document.write( "w - c - m = -155\r<BR>\n" );
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document.write( "subtract the second equation from the first to get -m + w = 60\r<BR>\n" );
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document.write( "rearrange the terms to get w - m = 60\r<BR>\n" );
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document.write( "subtract this equation from the third equation of w - c - m = -155 to get -c = -215\r<BR>\n" );
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document.write( "solve for c to get c = 215\r<BR>\n" );
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document.write( "in the equation of c = m + 35, replace c with 215 to get:\r<BR>\n" );
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document.write( "215 = m + 35\r<BR>\n" );
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document.write( "solve for m to get m = 180\r<BR>\n" );
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document.write( "you now have m = 180 and c = 215.\r<BR>\n" );
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document.write( "replace m and c in the third original equation to get:\r<BR>\n" );
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document.write( "w = c + m - 155 becomes w = 215 + 180 - 155\r<BR>\n" );
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document.write( "solve for w to get w = 240\r<BR>\n" );
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document.write( "you now have:\r<BR>\n" );
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document.write( "c = 215<BR>\n" );
document.write( "m = 180<BR>\n" );
document.write( "w = 240\r<BR>\n" );
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document.write( "go back to your original 3 equations and replace c and m and w with their respective values to see if those equations are all true.\r<BR>\n" );
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document.write( "your 3 original equations are:\r<BR>\n" );
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document.write( "c = m + 35<BR>\n" );
document.write( "c = w - 25<BR>\n" );
document.write( "w = c + m - 155\r<BR>\n" );
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document.write( "these become:\r<BR>\n" );
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document.write( "215 = 180 + 35, which is true.<BR>\n" );
document.write( "215 = 240 - 25, which is true.<BR>\n" );
document.write( "240 = 215 + 180 - 155, which is true.\r<BR>\n" );
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document.write( "all 3 original equations are true, therefore the solution looks good.\r<BR>\n" );
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document.write( "looks like:\r<BR>\n" );
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document.write( "country farms premium is 215.<BR>\n" );
document.write( "metma premium is 180.<BR>\n" );
document.write( "wisely premium is 240.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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