document.write( "Question 100533: There are 5 nickels, 3 dimes, and 2 quarters. What is the probability of selecting 1 nickel, 1 dime, and 1 quarter in any order with replacement? \n" ); document.write( "
Algebra.Com's Answer #73177 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! There are 5 nickels, 3 dimes, and 2 quarters. What is the probability of selecting 1 nickel, 1 dime, and 1 quarter in any order with replacement? \n" ); document.write( "---------------- \n" ); document.write( "\"With replacement\" makes all your selections independent. \n" ); document.write( "P(nickel)=5/10= 1/2 \n" ); document.write( "P(dime)=3/10 \n" ); document.write( "P(quarter)=2/10= 1/5 \n" ); document.write( "-------------- \n" ); document.write( "So, Prob(nickel dime quarter in any order) = 3!(30/1000) = 6(3/100)= 0.18 \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |