document.write( "Question 100472: Hello:\r
\n" ); document.write( "\n" ); document.write( "Thank you so much for offering the free tutoring.\r
\n" ); document.write( "\n" ); document.write( "My exercise is:\r
\n" ); document.write( "\n" ); document.write( "x^2+4x+4=7.\r
\n" ); document.write( "\n" ); document.write( "I have gotten to:\r
\n" ); document.write( "\n" ); document.write( "x^2+4x+4=7=0
\n" ); document.write( "x^2+4x+(-3)=0
\n" ); document.write( "now I am stuck.\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help.
\n" ); document.write( "

Algebra.Com's Answer #73176 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
The most common ways to solve a quadratic equation are by graphing, factoring, and completing
\n" ); document.write( "the square. Graphing has the disadvantage of being slow and requiring the scale to be
\n" ); document.write( "big enough so you can read it accurately. Factoring into a \"nice\" set of factors is not
\n" ); document.write( "always possible. (That is the case with this problem.) But completing the square can be
\n" ); document.write( "counted on to give you an answer. Using the quadratic formula is just a convenient
\n" ); document.write( "form of completing the square.
\n" ); document.write( ".
\n" ); document.write( "The quadratic formula says that if you can arrange the quadratic equation into the standard form:
\n" ); document.write( ".
\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\"
\n" ); document.write( ".
\n" ); document.write( "The solutions will be given by the equation:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( ".
\n" ); document.write( "You have worked your problem down to the form:
\n" ); document.write( ".
\n" ); document.write( "\"x%5E2%2B4x%2B%28-3%29=0\"
\n" ); document.write( ".
\n" ); document.write( "Let's just remove the parentheses on the left side to make the equation:
\n" ); document.write( ".
\n" ); document.write( "\"x%5E2%2B4x-3=0\"
\n" ); document.write( ".
\n" ); document.write( "Notice that this compares to the standard form in which a = +1, b = +4, and c = -3.
\n" ); document.write( "Therefore, you can go to the solutions equation and substitute these values of a, b, and c
\n" ); document.write( "into it to get the answers for x.
\n" ); document.write( ".
\n" ); document.write( "Start with the solutions equation:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( ".
\n" ); document.write( "and substitute +1 for a, +4 for b, and -3 for c to get:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+%28-%284%29+%2B-+sqrt%28+%284%29%5E2-4%2A1%2A%28-3%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( ".
\n" ); document.write( "within the radical sign note that \"4%5E2=+16\" and \"-4%2A1%2A%28-3%29+=+12\". Substituting
\n" ); document.write( "these into the radical simplifies the equation to:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+%28-%284%29+%2B-+sqrt%28++16%2B12%29%29%2F%282%2A1%29+\"
\n" ); document.write( ".
\n" ); document.write( "and the terms in the radical combine to 28 to give:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+%28-%284%29+%2B-+sqrt%2828%29%29%2F%282%2A1%29+\"
\n" ); document.write( ".
\n" ); document.write( "Note that the radical can be simplified. By the rules of radicals:\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%2828%29+=+sqrt%284%2A7%29+=+sqrt%284%29%2Asqrt%287%29+=+2%2Asqrt%287%29\"
\n" ); document.write( ".
\n" ); document.write( "Therefore, \"sqrt%2828%29\" can be replaced by \"2%2Asqrt%287%29\" and the answer equation
\n" ); document.write( "simplifies to:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+%28-%284%29+%2B-+2%2Asqrt%287%29%29%2F%282%2A1%29+\"
\n" ); document.write( ".
\n" ); document.write( "Now, remove the parentheses from -(4) to make it just -1 and multiply the 2*1 in the denominator
\n" ); document.write( "to get just 2. With these changes the answer equation simplifies to:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+%28-4+%2B-+2%2Asqrt%287%29%29%2F2+\"
\n" ); document.write( ".
\n" ); document.write( "So the two answers to your problem are:
\n" ); document.write( ".
\n" ); document.write( "\"x+=+%28-4+%2B+2%2Asqrt%287%29%29%2F2+\" and \"x+=+%28-4+-+2%2Asqrt%287%29%29%2F2+\"
\n" ); document.write( ".
\n" ); document.write( "You can approximate these answers by using a calculator to find that \"sqrt%287%29+=+2.645751311\"
\n" ); document.write( "and substituting that into the two answers results in:
\n" ); document.write( ".
\n" ); document.write( "
\n" ); document.write( ".
\n" ); document.write( "for one answer and
\n" ); document.write( ".
\n" ); document.write( "
\n" ); document.write( ".
\n" ); document.write( "for the other answer.
\n" ); document.write( ".
\n" ); document.write( "In summary, the two answers are x = 0.645751311 and x = -4.645751311
\n" ); document.write( ".
\n" ); document.write( "Hope this helps you to understand the problem a little better and gets you familiar with
\n" ); document.write( "using the quadratic formula as a method you can count on to solve a quadratic equation
\n" ); document.write( "that is giving you trouble.
\n" ); document.write( "
\n" ); document.write( "
\n" );