document.write( "Question 1116804: Three newspapers A, B and C are published in
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Algebra.Com's Answer #731709 by ikleyn(52788)\"\" \"About 
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document.write( "The percentage read at least one of the newspapers = (0.2 + 0.16 + 0.14 - 0.08 - 0.05 - 0.04 + 0.02)*100 = 35%.\r\n" );
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document.write( "    The first approximation is to add 20%, 16% and 14%.   (1) \r\n" );
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document.write( "    But in this way we count elements/(readers) in each intersection  AB, AC and AB twice.\r\n" );
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document.write( "    Therefore, we subtract 8%, 5% and 4%.                 (2)\r\n" );
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document.write( "    But in this way, we loose everything/(everybody) in the intersection ABC  (because we counted it/(them) thrice first in the step (1), \r\n" );
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document.write( "    and then excluded it/(them) thrice in the step (2). )\r\n" );
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document.write( "    Therefore, we add 2% as the last correction step.\r\n" );
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