document.write( "Question 1116768: A survey of 280 homeless persons showed that 63 were veterans. Construct a​ 90% confidence interval for the proportion of homeless persons who are veterans. \n" ); document.write( "
Algebra.Com's Answer #731697 by passionn(5)\"\" \"About 
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z=1.645
\n" ); document.write( "p=63/280=0.225
\n" ); document.write( "CI=p-z(√(p(1-p) )/n))≤Π\n" ); document.write( "CI=0.225-1645(√(0.225(1-0.225) )/280))≤Π<0.225+1.645(√(0.225(1-0.225)/280))
\n" ); document.write( "CI=0.184<Π<0.266
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