document.write( "Question 1116768: A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence interval for the proportion of homeless persons who are veterans. \n" ); document.write( "
Algebra.Com's Answer #731697 by passionn(5)![]() ![]() ![]() You can put this solution on YOUR website! z=1.645 \n" ); document.write( "p=63/280=0.225 \n" ); document.write( "CI=p-z(√(p(1-p) )/n))≤Π \n" );
document.write( "CI=0.225-1645(√(0.225(1-0.225) )/280))≤Π<0.225+1.645(√(0.225(1-0.225)/280)) |