document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1116781>Question 1116781</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the length of a diagonal of the cube with 3cm side length <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #731690 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=731690\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s be the length of a side, then use Pythagorean Theorem to get the diagonal(h) across the base<BR>\n" );
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document.write( "s^2 + s^2 = h^2<BR>\n" );
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document.write( "Use Pythagorean Theorem again to get the cube's diagonal(d)<BR>\n" );
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document.write( "h^2 + s^2 = d^2<BR>\n" );
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document.write( "substitute for h^2<BR>\n" );
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document.write( "s^2 + s^2 + s^2 = d^2<BR>\n" );
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document.write( "3s^2 = d^2<BR>\n" );
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document.write( "d = square root(3s^2) = s * square root(3)<BR>\n" );
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document.write( "cube diagonal is 3 * square root(3) approximately 5.2 cm<BR>\n" );
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