document.write( "Question 1116724: paul invested twice as much in an account paying 5% intrest as he did in an account paying 4% interest. If the total interest paid was $420.00, how much did he invest in each account?
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Algebra.Com's Answer #731629 by ikleyn(52812) $\"\"$ $\"About$

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document.write( "interest  + interest = total interest\r\n" );
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document.write( "0.05*(2x) + 0.04*x   = 420\r\n" );
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document.write( "0.1x + 0.04x = 420\r\n" );
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document.write( "0.14x = 420  ====>  x =  = 3000.\r\n" );
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document.write( "Answer.  $3000 was invested at 4%  and  $6000  was invested at 5%.\r\n" );
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document.write( "Check.   0.05*6000 + 0.04*3000 = 420.    ! Correct !\r\n" );
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