document.write( "Question 100359This question is from textbook texas algebra 2
\n" ); document.write( ": how do you write and graph an equation for
\n" ); document.write( "(A LINE PASSING) through (-2,1) and parallel to y=-2/3x-4 \n" ); document.write( "

Algebra.Com's Answer #73162 by oberobic(2304) $\"\"$ $\"About$

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Parallel lines have the same slope (by definition), so the slope of the line passing through the point(-2,1) will have to have slope = -2/3. We know that the line is sloping down to the right because the slope is negative. The slope is also the change in y divided by the change in x, so for each change of 3 on the x-axis, the y value decreases by 2 (that is, -2/3). To define a line, we need another point to pair with (-2,1).\r
\n" ); document.write( "\n" ); document.write( "We know that the general equation for a line is $\"y+=+mx+%2B+b\"$ . We know one y and one x, but we don't know b, so we substitute what we know and solve that.\r
\n" ); document.write( "\n" ); document.write( " $\"1+=+%28-2%2F3%29+%2A+-2+%2B+b\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"1+=+4%2F3+%2B+b\"$ so $\"b+=+-1%2F3\"$ \r
\n" ); document.write( "\n" ); document.write( "Recall the b is called the y-intercept, which tells us where the line crosses the y-axis when x=0. That gives us another coordinate pair: (0, -1/3). So the equation for the line is: \r
\n" ); document.write( "\n" ); document.write( " $\"y+=+%28-2%2F3%29x+-+1%2F3\"$ . \n" ); document.write( "

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