document.write( "Question 1116657: At a scrapbooking party, guests brought a certain number of photographs to use based on how many pages they will be assembling. Sharon plans to assemble three small pages and seven large pages and brought a total of 26 photographs to use. Whitney brought 16 photographs which is enough to assemble three small pages and two large pages assuming that the number of photographs on a page remains constant how many photographs fit on a small page and a large page? \n" ); document.write( "
Algebra.Com's Answer #731560 by josgarithmetic(39620)\"\" \"About 
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\n" ); document.write( "guests brought a certain number of photographs to use based on how many pages they will be assembling.
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\n" ); document.write( "Sharon plans to assemble three small pages and seven large pages and brought a total of 26 photographs to use.
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\n" ); document.write( "Whitney brought 16 photographs which is enough to assemble three small pages and two large pages
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\n" ); document.write( "...assuming that the number of photographs on a page remains constant how many photographs fit on a small page and a large page?
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\n" ); document.write( "\n" ); document.write( "That changes the description.\r
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\n" ); document.write( "\n" ); document.write( "What you really want to do is this:\r
\n" ); document.write( "\n" ); document.write( "Try making x and y, ratio of photos to pages for small page (x) and for large page (y). With this \"assumption\" and variables, form a system\r
\n" ); document.write( "\n" ); document.write( "\"system%283x%2B7y=26%2C3x%2B2y=16%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can eliminate the 3x to first find y; and use this y value to find x.\r
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\n" ); document.write( "\n" ); document.write( "\"y=2\"------photographs on a large page\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B2%2A2=16\"
\n" ); document.write( "\"3x=12\"
\n" ); document.write( "\"x=4\"-------photographs on a small page\r
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\n" ); document.write( "\n" ); document.write( "Those seem the reverse of what would be expected. Fewer on large page than on small page.
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